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5x^2+60x=324
We move all terms to the left:
5x^2+60x-(324)=0
a = 5; b = 60; c = -324;
Δ = b2-4ac
Δ = 602-4·5·(-324)
Δ = 10080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10080}=\sqrt{144*70}=\sqrt{144}*\sqrt{70}=12\sqrt{70}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-12\sqrt{70}}{2*5}=\frac{-60-12\sqrt{70}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+12\sqrt{70}}{2*5}=\frac{-60+12\sqrt{70}}{10} $
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